I'm wondering how many amps are being pulled on the primary 230V side when you put two of these Flatpacks in series and configured to max current. The datasheet says 11.6Amps at full load, but how does this work when you put two of them in series? Since the output current stays the same when putting two in series.. I'm confused a bit here
When calculating currents and volts from primary to secondary side it is easier to use wattage (power). Power out is power in times the efficiency in percentages.
if the output is at maximum current they deliver 2000 Watts. With an efficiency of 95% they draw 2000/0.95 = 2100 Watts from the mains EACH. 2 flatpacks in series is 2x 2100 Watt which equals 4200 Watt.
If the voltage is 230 Volt then the total current is 18.3 Amps (4200W/230V).
18.3 amps is more than 16 A (which is the normal rated current of the circuit breaker) BUT a circuit breaker has a characteristic which allows for 1.13 times the nominal current to be supplied for 3600 seconds (1 hour) before it trips. 1.13 times 16 Amps = a little over 18 amps so it is possible to use 2 flatpacks in series on 1 230 Volt outlet but only barely.
If you have just 2 flatpacks it is better is to use the three phase system (mennekes connector) and put the onboard charger on phase 1, the first flatpack on phase 2 and the second flatpack on phase 3. The onboard charger makes sure the contactor is activated. This way the currents are 6, 9 and 9 amps for the 3 phases.
If you have 4 flatpacks (for 80 amps output to the zero) it becomes more difficult on a three phase system. a 11 kW charging station COULD disconnect the supply after a few minutes (I've had that happen a few times. A 22 kW charging station should pose no problems as it has 32Amps output capabilities.
The stated 11.6 amps at full load but
also at minimum input voltage !!2100 Watts divided by 11.6 amps = 180 Volts.
So at 180 Volts input the flatpack draws 11.6 amps at full load.
But at 230 Volts input the flatpack draws 9.1 Amps at full load