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Author Topic: How about a 2013 FXU model?  (Read 9552 times)

protomech

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Re: How about a 2013 FXU model?
« Reply #15 on: November 17, 2012, 09:43:24 AM »

Keep in mind too that the graph is for a 2012 S. 2013 FX will have roughly 50% more power, probably 70-80% more wheel torque (at low speeds).
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trikester

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Re: How about a 2013 FXU model?
« Reply #16 on: November 17, 2012, 10:08:49 AM »

Quote
Keep in mind too that the graph is for a 2012 S. 2013 FX will have roughly 50% more power, probably 70-80% more wheel torque (at low speeds).

Whoopie!!!!!!!!!!

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NoiseBoy

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Re: How about a 2013 FXU model?
« Reply #17 on: November 17, 2012, 03:59:46 PM »

Keep in mind too that the graph is for a 2012 S. 2013 FX will have roughly 50% more power, probably 70-80% more wheel torque (at low speeds).

That's rather optimistic, the new sealed motor may be wound for more torque but the peak current is still limited by the same controller.
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trikester

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Re: How about a 2013 FXU model?
« Reply #18 on: November 17, 2012, 11:12:25 PM »

It is the 400 amp controller.

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NoiseBoy

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Re: How about a 2013 FXU model?
« Reply #19 on: November 17, 2012, 11:57:14 PM »

It is the 400 amp controller.

Trikester

So does the 2012S.  Electric motors have a linear torque curve, for the older motor you get roughly 0.15NM of torque per Ampere of input.  The new sealed unit is unlikely to be much different so it won't produce 80% more torque.
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trikester

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Re: How about a 2013 FXU model?
« Reply #20 on: November 18, 2012, 01:16:20 AM »

They list the torque for the 2013 FX at 95Nm (70 ft-lbs). I don't have the number for the 2012 DS (my present bike) at my fingertips, but I think it si quite a bit more than my 2012 DS.

Zero is claiming such a big improvement in efficiency of their new motor that they claim little cooling is needed, compared to the previous motor.

Time will tell  ;)

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protomech

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Re: How about a 2013 FXU model?
« Reply #21 on: November 18, 2012, 02:06:55 AM »

ME0913 does about 40 ft-lb.

Edit: so approximately 0.23 Nm/A.
« Last Edit: November 18, 2012, 02:09:32 AM by protomech »
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kingcharles

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Re: How about a 2013 FXU model?
« Reply #22 on: November 18, 2012, 04:43:24 AM »

It is the 400 amp controller.

Trikester

So does the 2012S.  Electric motors have a linear torque curve, for the older motor you get roughly 0.15NM of torque per Ampere of input.  The new sealed unit is unlikely to be much different so it won't produce 80% more torque.


But with the higher battery voltage of the 2013 bike those 400 amps will deliver more power compared to the 2012!
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NoiseBoy

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Re: How about a 2013 FXU model?
« Reply #23 on: November 18, 2012, 06:18:26 AM »

It is the 400 amp controller.

Trikester

So does the 2012S.  Electric motors have a linear torque curve, for the older motor you get roughly 0.15NM of torque per Ampere of input.  The new sealed unit is unlikely to be much different so it won't produce 80% more torque.


But with the higher battery voltage of the 2013 bike those 400 amps will deliver more power compared to the 2012!

More power yes, but not more torque.  Torque wins races.
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protomech

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Re: How about a 2013 FXU model?
« Reply #24 on: November 18, 2012, 09:24:51 AM »

Motor torque is a meaningless metric without RPM.
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trikester

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Re: How about a 2013 FXU model?
« Reply #25 on: November 18, 2012, 09:40:33 AM »

Torque is Ampere/turns. The higher voltage motor is going to have more turns if everything else remains the same (magnetic strength, etc). 400 amps + more turns = higher torque. Or if the magnets are stronger and the turns remain the same it will still be higher torque for the higher voltage. Certainly the higher operating voltage is producing higher torque if the current remains the same.

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NoiseBoy

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Re: How about a 2013 FXU model?
« Reply #26 on: November 18, 2012, 07:32:59 PM »

Motor torque is a meaningless metric without RPM.

How do you figure that when a motor makes peak torque at 0rpm?
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BSDThw

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Re: How about a 2013 FXU model?
« Reply #27 on: November 18, 2012, 08:08:24 PM »



P(Watt) = Torque * 2 * Pi * Frequency(Hz)

The KW / PS will increase linear with the RPM => 0 RPM is 0 PS but you have still full torque ???

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Richard230

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Re: How about a 2013 FXU model?
« Reply #28 on: November 18, 2012, 09:07:55 PM »

Motor torque is a meaningless metric without RPM.

How do you figure that when a motor makes peak torque at 0rpm?

Torque without movement is not producing any power. So you can have all the torque in the world, but if it is not moving something it is not doing any work and therefore is not producing any power. That is why you need rpm to go with your torque to generate power.

However, having a lot of torque throughout the motor's rpm range is a good thing, especially for street riding.  It means that you will have a broad spread of power throughout the rpm range of your motor and will not have to wait for the motor to rev up before being able to use that power to move something (like you) quickly.   :)
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trikester

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Re: How about a 2013 FXU model?
« Reply #29 on: November 19, 2012, 12:40:38 AM »

As I said; "torque is a function of ampere turns." When at 0 rpm you have "stall current" (highest current that can be forced through the resistance of the windings by the applied voltage, I = E/R) = max torque. :o

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